feat: working assembler! second pass implemenation. mnemonic parsing and binary construction and writing

This commit is contained in:
2026-02-24 14:10:09 +01:00
parent b968110397
commit 144179e0b8
8 changed files with 27579 additions and 29 deletions

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@@ -3,11 +3,9 @@
// by Nisan and Schocken, MIT Press.
// Computes R0 = 2 + 3 (R0 refers to RAM[0])
(lab)
@2
D=A
@3
D=D+A
(test)
@0
M=D

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@@ -1,2 +1,6 @@
// Assembled from Add.asm
// 12 lines processed
0000000000000010
1110110000010000
0000000000000011
1110000010010000
0000000000000000
1110001100001000

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@@ -6,12 +6,10 @@
// Computes R2 = max(R0, R1) (R0,R1,R2 refer to RAM[0],RAM[1],RAM[2])
// Usage: Before executing, put two values in R0 and R1.
// R0 = 10
// R1 = 15
// d = 10
// d = 10 - 15
// D = R0 - R1
/*
@R0
D=M
@R1
@@ -33,3 +31,36 @@
(END)
@END
0;JMP
*/
// Max
// Takes two numbers and saves the highest of them
// Get the sum of R0 & R1
// Save it in R2
// Get Value of R0
// Compare it value of R1
// Remember that the conditional can only be compared to zero.
// GT. LS, EQ etc.. All to zero
// Create a label and jump to it
@R0
D=M // Value of R0
@R1
D=D-M // New D(playground) is Old D(Value of R0) Minus Value of R1. Basically R0 - R1
@ITSR0
D;JGT // If D (R0 - R1) is greater than 0, then R0 is biger. Otherwise R1 or equal.
// Else it R1
// The end Statements
(ITSR0) // Jump here if R0
@R0
D=M // Set value of R0 to the playground variable.
(OUTPUT_D) // End up here either way. Depending on value.
@R2
M=D // Set R2 to D either way. Just with or without the ITSR0 iteration
(END) // The end final loop. Necessary to preven stack overflows.
@END
0;JMP // Infinite Jumping to end the program

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@@ -0,0 +1,16 @@
0000000000000000
1111110000010000
0000000000000001
1111010011010000
0000000000001010
1110001100000001
0000000000000001
1111110000010000
0000000000001100
1110101010000111
0000000000000000
1111110000010000
0000000000000010
1110001100001000
0000000000001110
1110101010000111

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