wip: CPU implementation

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2026-02-09 08:44:30 +01:00
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// This file is part of www.nand2tetris.org
// and the book "The Elements of Computing Systems"
// by Nisan and Schocken, MIT Press.
// File name: projects/5/CPU.hdl
/**
* The Hack Central Processing unit (CPU).
* Parses the binary code in the instruction input and executes it according to the
* Hack machine language specification. In the case of a C-instruction, computes the
* function specified by the instruction. If the instruction specifies to read a memory
* value, the inM input is expected to contain this value. If the instruction specifies
* to write a value to the memory, sets the outM output to this value, sets the addressM
* output to the target address, and asserts the writeM output (when writeM = 0, any
* value may appear in outM).
* If the reset input is 0, computes the address of the next instruction and sets the
* pc output to that value. If the reset input is 1, sets pc to 0.
* Note: The outM and writeM outputs are combinational: they are affected by the
* instruction's execution during the current cycle. The addressM and pc outputs are
* clocked: although they are affected by the instruction's execution, they commit to
* their new values only in the next cycle.
*/
CHIP CPU {
IN inM[16], // M value input (M = contents of RAM[A])
instruction[16], // Instruction for execution
reset; // Signals whether to re-start the current
// program (reset==1) or continue executing
// the current program (reset==0).
OUT outM[16], // M value output
writeM, // Write to M?
addressM[15], // Address in data memory (of M)
pc[15]; // address of next instruction
PARTS:
// Instructions.
// Decode the instruction bit.
// i xx a cccccc ddd jjj
// For C-Instruction the byte is stored as i(opcode) xx(notUsed) a cccccc(a/c = comp) ddd(destination) jjj(jump)
// i xxxxxxxxxxxxxxx
// For A-Instruction the i(opcode) is 0 and the rest is the 16(15)-bit value that is stored there.
// Decode Instruction
Not(in=instruction[15], out=isAInstruction); // Flip it and if 1 it's an A Instruction
And(a=instruction[15], b=true, out=isCInstruction); // Check it with an And static true to check if both 1 then it's C instruction.
// Don't need decoding for the rest when A instruction.
// Just use instruction because instruction[15] will always be 0
// Decode C & Create Wires
// 1xA
And(a=instruction[12], b=true , out=a1);
// 6xC
And(a=instruction[11], b=true , out=c1);
And(a=instruction[10], b=true , out=c2);
And(a=instruction[9], b=true , out=c3);
And(a=instruction[8], b=true , out=c4);
And(a=instruction[7], b=true , out=c5);
And(a=instruction[6], b=true , out=c6);
// 3xD
And(a=instruction[5], b=true , out=d1);
And(a=instruction[4], b=true , out=d2);
And(a=instruction[3], b=true , out=d3);
// 3xJ
And(a=instruction[2], b=true , out=j1);
And(a=instruction[1], b=true , out=j2);
And(a=instruction[0], b=true , out=j3);
// aluOut is not made yet
// A Register
// Should Load from ALU if
And(a=isCInstruction, b=d1, out=loadAFromALU);
Mux16(a=instruction, b=aluOut, sel=loadAFromALU,out=aRegIn);
Or(a=isAInstruction, b=loadAFromALU, out=loadA);
Register(in=aRegIn, load=loadA, out=aRegOut);
// D Register
And(a=isCInstruction, b=d2, out=loadD);
Register(in=aluOut, load=loadD, out=dRegOut);
// a - instruction12 - a1
// a=0 → use A register
// a=1 → use M (inM from memory)
// ALU
Mux16(a=aRegOut, b=inM , sel=a1 , out=aluYin);
ALU(x=dRegOut,
y=aluYin,
zx=c1, nx=c2, zy=c3, ny=c4 , f=c5 , no=c6 ,
out=aluOut ,
zr=aluZrOut ,
ng=aluNgOut
);
}